Jawaban:
[tex]\bf\large F=4,05×10¹²\ Newton [/tex]
Penjelasan:
[tex]\sf\large Diketahui; [/tex]
[tex]\sf\large{Q_{A} = 6\ C }[/tex]
[tex]\sf\large{Q_{B} =3\ C }[/tex]
[tex]\sf\large{r = 20\ cm = 2×10^{-1}\ m }[/tex]
[tex]\sf\large{k = 9×10⁹\ Nm²/C² }[/tex]
Ditanyakan nilai gaya Coulomb.
Jawab;
Gunakan rumus;
[tex]\sf\large{F.r² = k.Q_{1}.Q₂ }[/tex]
[tex]\sf\large{F} = \LARGE{\frac{k.Q_{1}.Q₂}{r²} }[/tex]
[tex]\sf\large{F} =\LARGE{\frac{9×10⁹.6.3}{(2×10^{-1})²}=\frac{9.6.3×10⁹}{4×10^{-2}} }[/tex]
[tex]\sf\large{F} =\LARGE{\frac{162×10^{9+2}}{4}=\frac{162×10¹¹}{4} }[/tex]
[tex]\sf\large{F =4,05×10¹² \ N }[/tex]
Jadi gaya Coulomb-nya sebesar [tex]\sf\large4,05×10¹²\ Newton [/tex]
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